Find the zeros of 49x^2 - 64 .
Solñ
1. Let p(x)=0
49x^2 - 64 =0
(7x)^2 - 8^2 =●
(7x)^2 = 8^2
=>x = +- 8/7
Since value of x is square.

2. 49x^2 - 64 =0
(7x)^2 - 8^2=0
(7x +8).(7x-8)=0
X=+- 8/7

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