Shine Rose Sarkar   (Shine Rose)
25 Followers · 13 Following

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Joined 11 September 2018


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Joined 11 September 2018
10 JUN 2020 AT 13:14

❤❤❤❤❤❤❤❤❤❤❤❤❤❤

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27 OCT 2019 AT 22:30

Happy Dipawali to all of u ❤

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12 AUG 2019 AT 11:21

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ I and My Dear Papa and My mama❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

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12 AUG 2019 AT 11:18

Hi friends

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12 AUG 2019 AT 11:13

Happy IDD mubarak

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18 FEB 2019 AT 23:14

Find the zeros of 49x^2 - 64 .
Solñ
1. Let p(x)=0
49x^2 - 64 =0
(7x)^2 - 8^2 =●
(7x)^2 = 8^2
=>x = +- 8/7
Since value of x is square.

2. 49x^2 - 64 =0
(7x)^2 - 8^2=0
(7x +8).(7x-8)=0
X=+- 8/7

Shine Rose Sarkar
Bsc (Royal)
G.U

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11 SEP 2018 AT 17:44


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